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What is the most efficient way to solve a problem
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- Is there an efficient way to solve this problem?
- http://blogs.ft.com/undercover/2008/09/dear-economist-do-olympic-judges-need-a-profit-motive/
- In a sport whose entire aim is to win the approval of the judges, error is unavoidable. Yet (as the sports economist Stefan Szymanski reminds me) there is a trade-off here between two sorts of error: bias and variance. The decision to use d...
- What is the most cost-efficient way to cushion this problem??
- http://www.kstan.net/s/keyman.htm#cost
- Due recognition must be given to this aspect of the business and every organization must therefore take the necessary steps to minimize the loss of key persons as a result of death or permanent disability. The simplest and most cost-efficie...
- Is a housing supplement to the EITC an effective and efficient wa...?
- http://www.nhi.org/online/issues/151/creditdue.html
- To state the obvious, increasing the amount of money that families receive through the EITC will give them more income, and thereby reduce housing costs as a share of income (or enable families to move to better housing). The anti-poverty p...
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- What is the most efficient method of solving this mathematical problem? 25 X ?^50 = 1300?
- Q: I am trying to work out the the interest rate required to turn £25 in 1300 in 50 years. The interest is compounded so please dont simply post the average rate. I know there is a simple method for calculating this but cannot remember what it is!Many Thanks
- A: what's the compounding interval? the general compound interest formula is:1300 = 25(1 + r/n) ^(50n) (where n is the number of compounding intervals per year)assuming that n = 1, then1300 = 25(1 + r)^(50)52 = (1 + r)^50tak the 50th root of both sides:52^(1/50) = 1 + rr = 52^(1/50) - 1r will be the annual interest rate as a decimal-- .0822this corresponds to 8.22% APRif it compounds more than once a year, just replace n with the number of compounding intervals ex: daily compounding ==> n = 3651300 = 25(1 + r/365)^(50 * 365)52 = (1 + r/365) ^(50 * 365) since 50 * 365 = 18250, you'll have to take the 18250th root of both sides52^(1/18250) = 1 + r/365now subtract 152^(1/18250) - 1 = r / 365and multiply by 365365(52^(1/18250) - 1) = .079, or 7.90%the daily compounding allows for a slightly lower APR to achieve the goaland what the heck...for continuous compounding:1300 = 25e^(50r)52 = e^(50r)okay, now you do need logs!ln 52 = 50rr = (ln 52)/50r = .0790, or 7.90%-- not a whole log of difference between daily and continuous compounding over those 50 years!
- Why can't we solve the high gas price problem with more efficient cars? Surely engineers can design them.
- Q: If we could double or triple gas mileage, prices would fall, and our country would boom.
- A: because of high price in world market
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